When the trigger is squeezed on a revolver, what sequence occurs?

When the trigger is squeezed on a revolver, what sequence occurs?

• A. The cylinder unlocks and rotates; the hammer falls and strikes the primer.
• B. The barrel extends.
• C. The hammer locks the cylinder in place.
• D. The ejector rod advances.

Answer: (A)

In a double-action revolver, pulling the trigger performs two actions at once. As you squeeze, the mechanism rotates the cylinder to bring a fresh cartridge into alignment with the barrel and, at the same time, cocks the hammer. When the trigger reaches the point of release, the hammer falls and strikes the primer, firing the cartridge. The barrel and frame stay fixed during this sequence, and the cylinder is held in place by the cylinder stop after it aligns a chamber. The ejector rod doesn’t move during this firing step; it only advances when you unload spent casings later.

In a double-action revolver, pulling the trigger performs two actions at once. As you squeeze, the mechanism rotates the cylinder to bring a fresh cartridge into alignment with the barrel and, at the same time, cocks the hammer. When the trigger reaches the point of release, the hammer falls and strikes the primer, firing the cartridge. The barrel and frame stay fixed during this sequence, and the cylinder is held in place by the cylinder stop after it aligns a chamber. The ejector rod doesn’t move during this firing step; it only advances when you unload spent casings later.